mysql oracle sql获取树 父级 子级 及自己

       select * from ( select t.*,d.TABLE_NAME,d.QUERY_SQL,d.data_control_col,d.id table_id,d.where_sql
        from REPORT_KPI_INFO t
        left join REPORT_KPI_TABLE_INFO d
        on t.id = d.kpi_id
        where t.kpi_status=1
        <if test="keyword != null and keyword != ''">
            and t.id in
            (select t.id
            from REPORT_KPI_INFO t
            start with t.id in (select t.id
            from REPORT_KPI_INFO t
            where t.kpi_name like '%'||#{keyword}||'%')
            connect by t.id = prior t.parent_id)
            union

            select t.*,
            d.TABLE_NAME,
            d.QUERY_SQL,
            d.data_control_col,
            d.id table_id,
            d.where_sql
            from REPORT_KPI_INFO t
            left join REPORT_KPI_TABLE_INFO d
            on t.id = d.kpi_id
            where t.kpi_status = 1
            and t.id in
            (select t.id
            from REPORT_KPI_INFO t
            start with t.id in (select t.id
            from REPORT_KPI_INFO t
            where t.kpi_name like '%'||#{keyword}||'%')
            connect by prior t.id = t.parent_id)
        </if>
        )
        order by to_number(kpi_sort)
posted @ 2019-12-18 14:25  剑小新  阅读(546)  评论(0编辑  收藏  举报