topcoder srm 550
div1 250pt:
题意：有个机器人，从某一点出发，他只有碰到地形边缘或者碰到走过的点时才会改变运动方向，然后接着走，现在给出他的运动轨迹，判断他的运动是否合法，如果合法的话，那么整个地形的最小面积是多少。
解法：先随便设定一个起点，然后模拟机器人走的路线，先确定出来运动的大致范围，然后判断运动轨迹是否合法，也就是出了最后一步可以手动终止之外，看其他的时候，它转变方向是不是合法。。。。
1 // BEGIN CUT HERE 2 3 // END CUT HERE 4 #line 5 "RotatingBot.cpp" 5 #include<cstdio> 6 #include<sstream> 7 #include<cstring> 8 #include<cstdlib> 9 #include<ctime> 10 #include<cmath> 11 #include<cassert> 12 #include<iostream> 13 #include<string> 14 #include<vector> 15 #include<map> 16 #include<set> 17 #include<queue> 18 #include<stack> 19 #include<algorithm> 20 using namespace std; 21 typedef long long ll; 22 typedef pair<int,int> pii; 23 int vis[1000][1000]; 24 int dir[4][2] = {1,0,0,1,-1,0,0,-1}; 25 class RotatingBot 26 { 27 public: 28 int minArea(vector <int> moves){ 29 //$CARETPOSITION$ 30 memset(vis,-1,sizeof(vis)); 31 int cur_d = 0; 32 int cur_x = 500,cur_y = 500; 33 vis[cur_x][cur_y] = 0; 34 for(int i = 0;i < moves.size();i++){ 35 int len = moves[i]; 36 while(len > 0){ 37 cur_x += dir[cur_d][0]; 38 cur_y += dir[cur_d][1]; 39 if(vis[cur_x][cur_y] != -1)return -1; 40 vis[cur_x][cur_y] = i; 41 len --; 42 } 43 cur_d = (cur_d + 1) % 4; 44 } 45 // cout << "done" <<endl; 46 int left = 999,right = 0,top = 0,bottom = 999; 47 for(int i = 0;i < 1000;i++) 48 for(int j = 0;j < 1000;j++){ 49 if(vis[i][j] != -1){ 50 left = min(left,i); 51 right = max(right,i); 52 top = max(top,j); 53 bottom = min(bottom,j); 54 } 55 } 56 // cout <<"left: "<<left<<" right: "<<right <<" top: "<<top<<" bottom:"<<bottom<<endl; 57 cur_x = 500,cur_y = 500;cur_d = 0; 58 for(int i = 0;i < moves.size();i++){ 59 int len = moves[i]; 60 while(len > 0){ 61 cur_x += dir[cur_d][0]; 62 cur_y += dir[cur_d][1]; 63 len --; 64 } 65 if(i == moves.size() - 1)continue; 66 int next_x = cur_x + dir[cur_d][0]; 67 int next_y = cur_y + dir[cur_d][1]; 68 if(next_x >= left && next_x <= right && next_y >= bottom && next_y <= top){ 69 if(vis[next_x][next_y] == -1)return -1; 70 if(vis[next_x][next_y] > i)return -1; 71 } 72 cur_d = (cur_d + 1) % 4; 73 } 74 return (right - left + 1) * (top - bottom + 1); 75 76 } 77 78 // BEGIN CUT HERE 79 public: 80 void run_test(int Case) { if ((Case == -1) || (Case == 0)) test_case_0(); if ((Case == -1) || (Case == 1)) test_case_1(); if ((Case == -1) || (Case == 2)) test_case_2(); if ((Case == -1) || (Case == 3)) test_case_3(); if ((Case == -1) || (Case == 4)) test_case_4(); if ((Case == -1) || (Case == 5)) test_case_5(); if ((Case == -1) || (Case == 6)) test_case_6(); if ((Case == -1) || (Case == 7)) test_case_7(); } 81 private: 82 template <typename T> string print_array(const vector<T> &V) { ostringstream os; os << "{ "; for (typename vector<T>::const_iterator iter = V.begin(); iter != V.end(); ++iter) os << '\"' << *iter << "\","; os << " }"; return os.str(); } 83 void verify_case(int Case, const int &Expected, const int &Received) { cerr << "Test Case #" << Case << "..."; if (Expected == Received) cerr << "PASSED" << endl; else { cerr << "FAILED" << endl; cerr << "\tExpected: \"" << Expected << '\"' << endl; cerr << "\tReceived: \"" << Received << '\"' << endl; } } 84 void test_case_0() { int Arr0[] = {15}; vector <int> Arg0(Arr0, Arr0 + (sizeof(Arr0) / sizeof(Arr0[0]))); int Arg1 = 16; verify_case(0, Arg1, minArea(Arg0)); } 85 void test_case_1() { int Arr0[] = {3,10}; vector <int> Arg0(Arr0, Arr0 + (sizeof(Arr0) / sizeof(Arr0[0]))); int Arg1 = 44; verify_case(1, Arg1, minArea(Arg0)); } 86 void test_case_2() { int Arr0[] = {1,1,1,1}; vector <int> Arg0(Arr0, Arr0 + (sizeof(Arr0) / sizeof(Arr0[0]))); int Arg1 = -1; verify_case(2, Arg1, minArea(Arg0)); } 87 void test_case_3() { int Arr0[] = {9,5,11,10,11,4,10}; vector <int> Arg0(Arr0, Arr0 + (sizeof(Arr0) / sizeof(Arr0[0]))); int Arg1 = 132; verify_case(3, Arg1, minArea(Arg0)); } 88 void test_case_4() { int Arr0[] = {12,1,27,14,27,12,26,11,25,10,24,9,23,8,22,7,21,6,20,5,19,4,18,3,17,2,16,1,15}; vector <int> Arg0(Arr0, Arr0 + (sizeof(Arr0) / sizeof(Arr0[0]))); int Arg1 = 420; verify_case(4, Arg1, minArea(Arg0)); } 89 void test_case_5() { int Arr0[] = {8,6,6,1}; vector <int> Arg0(Arr0, Arr0 + (sizeof(Arr0) / sizeof(Arr0[0]))); int Arg1 = -1; verify_case(5, Arg1, minArea(Arg0)); } 90 void test_case_6() { int Arr0[] = {8,6,6}; vector <int> Arg0(Arr0, Arr0 + (sizeof(Arr0) / sizeof(Arr0[0]))); int Arg1 = 63; verify_case(6, Arg1, minArea(Arg0)); } 91 void test_case_7() { int Arr0[] = {5,4,5,3,3}; vector <int> Arg0(Arr0, Arr0 + (sizeof(Arr0) / sizeof(Arr0[0]))); int Arg1 = 30; verify_case(7, Arg1, minArea(Arg0)); } 92 93 // END CUT HERE 94 95 }; 96 // BEGIN CUT HERE 97 int main(){ 98 RotatingBot ___test; 99 ___test.run_test(-1); 100 return 0; 101 } 102 // END CUT HERE
div1 500pt:
题意:两个人在一个无限大的格子里涂色，第一个人先在(0,0)涂色，然后接下来的每一轮，对于所有的点(x,y)，如果(x-1,y-1)和(x-2,y)中有且只有一个点被涂色了，那么就把这个点也涂了，问经过t轮之后，某个区域的染色情况。
解法：先在纸上模拟一下前几轮的情况，我们很容易发现，被涂色的区域就是{x>=0,y>=0并且x<=y}这部分区域，而且被涂色点的分布很像一个杨辉三角，其中被涂色的部分就是杨辉三角中奇数的点。。。于是问题就变成判断C(n,m)奇偶性的问题了，有个结论C(n,m)是奇数当且仅当n&m==n。。。
1 // BEGIN CUT HERE 2 3 // END CUT HERE 4 #line 5 "CheckerExpansion.cpp" 5 #include<cstdio> 6 #include<sstream> 7 #include<cstring> 8 #include<cstdlib> 9 #include<ctime> 10 #include<cmath> 11 #include<cassert> 12 #include<iostream> 13 #include<string> 14 #include<vector> 15 #include<map> 16 #include<set> 17 #include<queue> 18 #include<stack> 19 #include<algorithm> 20 using namespace std; 21 typedef long long ll; 22 typedef pair<int,int> pii; 23 class CheckerExpansion 24 { 25 public: 26 vector <string> resultAfter(long long t, long long x0, long long y0, int w, int h){ 27 //$CARETPOSITION$ 28 vector<string> ret; 29 // t = 5;x0 = 0;y0 = 0;w = 10;h = 10; 30 for(int i = 0;i < h;i++){ 31 string tmp = ""; 32 for(int j = 0;j < w;j++){ 33 char will; 34 long long x = x0 + j; 35 long long y = y0 + h - i - 1; 36 // if(x == y)cout <<"x : " <<x<<" y:"<<y<<endl; 37 if((x + y) % 2 == 0){ 38 if(x < y){ 39 will = '.'; 40 }else{ 41 long long row = (x + y) / 2; 42 long long column = abs(x - row); 43 if(row + 1> t){ 44 will = '.'; 45 }else if((row & column) == column){ 46 if(row % 2 == 0){ 47 will = 'A'; 48 }else{ 49 will = 'B'; 50 } 51 }else{ 52 will = '.'; 53 } 54 } 55 }else{ 56 will = '.'; 57 } 58 // if(x == y)cout<<will<<endl; 59 tmp += will; 60 } 61 ret.push_back(tmp); 62 // cout << tmp << endl; 63 64 } 65 return ret; 66 67 68 } 69 70 // BEGIN CUT HERE 71 public: 72 void run_test(int Case) { if ((Case == -1) || (Case == 0)) test_case_0(); if ((Case == -1) || (Case == 1)) test_case_1(); if ((Case == -1) || (Case == 2)) test_case_2(); if ((Case == -1) || (Case == 3)) test_case_3(); } 73 private: 74 template <typename T> string print_array(const vector<T> &V) { ostringstream os; os << "{ "; for (typename vector<T>::const_iterator iter = V.begin(); iter != V.end(); ++iter) os << '\"' << *iter << "\","; os << " }"; return os.str(); } 75 void verify_case(int Case, const vector <string> &Expected, const vector <string> &Received) { cerr << "Test Case #" << Case << "..."; if (Expected == Received) cerr << "PASSED" << endl; else { cerr << "FAILED" << endl; cerr << "\tExpected: " << print_array(Expected) << endl; cerr << "\tReceived: " << print_array(Received) << endl; } } 76 void test_case_0() { long long Arg0 = 1LL; long long Arg1 = 0LL; long long Arg2 = 0LL; int Arg3 = 4; int Arg4 = 4; string Arr5[] = {"....", "....", "....", "A..." }; vector <string> Arg5(Arr5, Arr5 + (sizeof(Arr5) / sizeof(Arr5[0]))); verify_case(0, Arg5, resultAfter(Arg0, Arg1, Arg2, Arg3, Arg4)); } 77 void test_case_1() { long long Arg0 = 5LL; long long Arg1 = 4LL; long long Arg2 = 1LL; int Arg3 = 3; int Arg4 = 4; string Arr5[] = {"A..", "...", "B..", ".B." }; vector <string> Arg5(Arr5, Arr5 + (sizeof(Arr5) / sizeof(Arr5[0]))); verify_case(1, Arg5, resultAfter(Arg0, Arg1, Arg2, Arg3, Arg4)); } 78 void test_case_2() { long long Arg0 = 1024LL; long long Arg1 = 1525LL; long long Arg2 = 512LL; int Arg3 = 20; int Arg4 = 2; string Arr5[] = {"B...B...B...........", ".B.A.B.A.B.........." }; vector <string> Arg5(Arr5, Arr5 + (sizeof(Arr5) / sizeof(Arr5[0]))); verify_case(2, Arg5, resultAfter(Arg0, Arg1, Arg2, Arg3, Arg4)); } 79 void test_case_3() { long long Arg0 = 53LL; long long Arg1 = 85LL; long long Arg2 = 6LL; int Arg3 = 5; int Arg4 = 14; string Arr5[] = {".....", ".....", "B....", ".B.A.", ".....", ".....", ".....", ".....", ".....", ".....", "B....", ".B...", "..B..", ".A.B." }; vector <string> Arg5(Arr5, Arr5 + (sizeof(Arr5) / sizeof(Arr5[0]))); verify_case(3, Arg5, resultAfter(Arg0, Arg1, Arg2, Arg3, Arg4)); } 80 81 // END CUT HERE 82 83 }; 84 // BEGIN CUT HERE 85 int main(){ 86 CheckerExpansion ___test; 87 ___test.run_test(-1); 88 return 0; 89 } 90 // END CUT HERE
