python--斐波那契数列

# 斐波那契数列 100以内
# f(n) = f(n-1) + f(n -2)
# 第一个数加第二个数等于第三个数

a = 0
b = 1
while True:
    c = a + b
    if c > 100:
        break
    a = b
    b = c
    print(c)

# 求斐波那契数列第101项

num = int(input(">>> 输入打印第几项："))
n1 = 0  # 上次结果
n2 = 1  # 当前结果
tmp = 0  # 临时存放
for i in range(1, num):
    tmp = n1 + n2
    n1 = n2
    n2 = tmp
print(n2)

###########################################

# 从1开始循环30次的斐波那契数列
# 循环次数
for_num = 30
num_01 = 0
num_02 = 1
for _ in range(for_num - 1):
    num_01, num_02 = num_02, num_01 + num_02
    # if num_02 < 100:
    # print(num_02)
    print(num_02)

#############################

# 给出一个数字，得出该范围内的所有斐波那契数列。并统计个数
scope_num = 1000  # 数字范围
count = 0  # 统计次数
num_01 = 0  # 第一个数
num_02 = 1  # 第二个数

while True:
    num_01, num_02 = num_02, num_01 + num_02
    if num_02 < scope_num:
        print(num_02)
    else:
        break
    count += 1
print("{} 内的个数为：{}".format(scope_num, count))