摘要: def cross(A,B): return A[0] * B[1] - A[1] * B[0] def vectorMinus( a , b): return ( (a[0] - b[0] )*1000,(a[1] - b[1] )*1000) def getLTDis( A, B ): lon1, lat1, lon2, lat2 = map(radians, [... 阅读全文
posted @ 2016-08-26 14:33 默默无语敲代码 阅读(2268) 评论(0) 推荐(1) 编辑