摘要: SET @json = '["a", "b", "b", "a", "c"]';SELECT Json_arrayagg(dt.val) AS unq_json_arrayFROM (SELECT DISTINCT Json_extract(@json, Concat('$[', seq.n, '] 阅读全文
posted @ 2020-11-17 09:49 开顺 阅读(2202) 评论(1) 推荐(0) 编辑