CodeForces - 1059B - Forgery(模拟)
题目链接:https://vjudge.net/problem/CodeForces-1059B
题目大意:你有一个可以盖出一个3*3 ‘#’中心为‘.’的章,问你能不能盖出图中的形状
其实简单模拟一下就行了.....如果盖下一个章,那么这个章的中心8个方向一定是'#',那我们反过来做一个'.'图,只要原图某个点的8个方向都是'#',那我们就以这个点为中心盖一个章,最后对比一下我们构造的图和原图,如果不一样,那肯定是无法盖出图中的形状的.
#include<set> #include<map> #include<stack> #include<queue> #include<cmath> #include<cstdio> #include<cctype> #include<string> #include<vector> #include<climits> #include<cstring> #include<cstdlib> #include<iostream> #include<algorithm> #define endl '\n' #define rtl rt<<1 #define rtr rt<<1|1 #define lson rt<<1, l, mid #define rson rt<<1|1, mid+1, r #define maxx(a, b) (a > b ? a : b) #define minn(a, b) (a < b ? a : b) #define zero(a) memset(a, 0, sizeof(a)) #define INF(a) memset(a, 0x3f, sizeof(a)) #define IOS ios::sync_with_stdio(false) #define _test printf("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\n") using namespace std; typedef long long ll; typedef pair<int, int> P; typedef pair<ll, ll> P2; const double pi = acos(-1.0); const double eps = 1e-7; const ll MOD = 1000000007LL; const int INF = 0x3f3f3f3f; const int _NAN = -0x3f3f3f3f; const double EULC = 0.5772156649015328; const int NIL = -1; template<typename T> void read(T &x){ x = 0;char ch = getchar();ll f = 1; while(!isdigit(ch)){if(ch == '-')f*=-1;ch=getchar();} while(isdigit(ch)){x = x*10+ch-48;ch=getchar();}x*=f; } const int maxn = 1e3+10; char omap[maxn][maxn], vmap[maxn][maxn]; int dir[8][2] = {{-1, -1}, {-1, 0}, {-1, 1}, {0, -1}, {0, 1}, {1, -1}, {1, 0}, {1, 1}}; bool ok(int x, int y) { for (int i = 0; i<8; ++i) { int newx = x+dir[i][0], newy = y+dir[i][1]; if (omap[newx][newy]=='.') return false; } return true; } void make(int x, int y) { for (int i = 0; i<8; ++i) { int newx = x+dir[i][0], newy = y+dir[i][1]; vmap[newx][newy] = '#'; } } bool checker(int n, int m) { for (int i = 0; i<n; ++i) for (int j = 0; j<m; ++j) if (omap[i][j]!=vmap[i][j]) return false; return true; } int main(void) { int n, m; while(~scanf("%d%d", &n, &m)) { for (int i = 0; i<n; ++i) scanf("%s", omap[i]); for (int i = 0; i<n; ++i) //全部初始化为.图 for (int j = 0; j<m; ++j) vmap[i][j] = '.'; for (int i = 1; i<n-1; ++i) for (int j = 1; j<m-1; ++j) //参考样例2,中心不能在边缘 if (ok(i, j)) make(i, j); //如果一个点8个方向都有#那么就以这个点为中心盖一个章 printf(checker(n, m) ? "YES\n" : "NO\n"); //对比两个图是否一样 } return 0; }