摘要: UPDATE card SET value = (SELECT value FROM card WHERE id = 23) WHERE id = 20;更新时 在where条件里面加入的子查询导致的。解决方法:UPDATE card SET value = (SELECT val FROM (SE... 阅读全文
posted @ 2014-10-14 14:12 廖东海 阅读(312) 评论(0) 推荐(0) 编辑