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摘要: 循环多少次? Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6539 Accepted Submission(s): 2524 Problem 阅读全文
posted @ 2019-02-16 21:21 守林鸟 阅读(292) 评论(0) 推荐(0) 编辑
摘要: 算法训练 最大最小公倍数 时间限制:1.0s 内存限制:256.0MB 问题描述 已知一个正整数N,问从1~N中任选出三个数,他们的最小公倍数最大可以为多少。 输入格式 输入一个正整数N。 输出格式 输出一个整数,表示你找到的最小公倍数。 样例输入 9 样例输出 504 数据规模与约定 1 <= N 阅读全文
posted @ 2019-02-15 20:19 守林鸟 阅读(611) 评论(0) 推荐(0) 编辑
摘要: Turing Tree Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7323 Accepted Submission(s): 2654 Pro 阅读全文
posted @ 2019-02-14 15:30 守林鸟 阅读(340) 评论(0) 推荐(0) 编辑
摘要: Longge is good at mathematics and he likes to think about hard mathematical problems which will be solved by some graceful algorithms. Now a problem c 阅读全文
posted @ 2019-02-14 00:18 守林鸟 阅读(190) 评论(0) 推荐(0) 编辑
摘要: The greatest common divisor GCD(a,b) of two positive integers a and b,sometimes written (a,b),is the largest divisor common to a and b,For example,(1, 阅读全文
posted @ 2019-02-13 22:11 守林鸟 阅读(255) 评论(0) 推荐(0) 编辑
摘要: 逆元概念:p是素数,在%p的情况下,如果 ( a*inv(a) ) ≡ 1 (%p),则inv(a)是a的乘法逆元 费马小定理概念:如果p是素数,a和p互质,即gcd(a,p)=1,则 a^(p-1)≡ 1 ( %p ) 则a^(p-2) (mod p) 就是a在模p意义下的逆元 费马小定理下,in 阅读全文
posted @ 2019-02-13 12:56 守林鸟 阅读(1319) 评论(0) 推荐(0) 编辑
摘要: YAPTCHA Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1490 Accepted Submission(s): 811 Problem 阅读全文
posted @ 2019-02-12 20:08 守林鸟 阅读(148) 评论(0) 推荐(0) 编辑
摘要: Tina Town is a friendly place. People there care about each other. Tina has a ball called zball. Zball is magic. It grows larger every day. On the fir 阅读全文
posted @ 2019-02-12 17:26 守林鸟 阅读(174) 评论(0) 推荐(0) 编辑
摘要: https://vjudge.net/problem/HDU-3579 Hello Kiki Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 54 阅读全文
posted @ 2019-02-11 23:47 守林鸟 阅读(267) 评论(0) 推荐(0) 编辑
摘要: X问题 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8416 Accepted Submission(s): 3066 Problem Des 阅读全文
posted @ 2019-02-11 22:45 守林鸟 阅读(206) 评论(0) 推荐(0) 编辑
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