hdu1002-A + B Problem II-（java大数）

A + B Problem II

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 460526    Accepted Submission(s): 89173

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

 

 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

 

 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

 

 

Sample Input

2 1 2 112233445566778899 998877665544332211

 

 

Sample Output

Case 1: 1 + 2 = 3 Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110

import java.math.BigInteger;//操作大型整数
import java.math.BigDecimal;//操作大型小数
import java.util.Scanner;
import java.util.Arrays;
public class Main//hdu1002
{
    public static void main(String []args)
    {    
        BigInteger a,b,sum;
        Scanner scan=new Scanner(System.in);
        int t;
        t=scan.nextInt();
        for(int i=1;i<=t;i++)
        {
            a=scan.nextBigInteger();
            b=scan.nextBigInteger();
            sum=a.add(b);
            System.out.println("Case "+i+":");
            System.out.println(a+" + "+b+" = "+sum);
            if(i!=t)
                System.out.println();    
        }
    }
}