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贵有恒何必三更眠五更起 最无益只怕一日曝十日寒

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1. 题目

读题

HJ87 密码强度等级

 

 

考查点

 

2. 解法

思路

 

代码逻辑

 

具体实现

public class HJ087 {
public static String[] grades = {"VERY_SECURE", "SECURE", "VERY_STRONG", "STRONG", "AVERAGE", "WEAK", "VERY_WEAK"};

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println(getPwdSecurityGrade(sc.nextLine()));
}

public static String getPwdSecurityGrade(String pwd) {
int score = 0;
int n = pwd.length();
if (n <= 4) {
score += 5;
} else if (n >= 5 && n <= 7) {
score += 10;
} else {
score += 25;
}

boolean upperFlag = false;
boolean lowerFlag = false;
int numCnt = 0;
int symbolCnt = 0;

for (char c : pwd.toCharArray()) {
if (c >= 'a' && c <= 'z') {
upperFlag = true;
} else if (c >= 'A' && c <= 'Z') {
lowerFlag = true;
} else if (c >= '0' && c <= '9') {
numCnt++;
} else {
symbolCnt++;
}
}

if (upperFlag && lowerFlag) {
score += 20;
} else if (upperFlag || lowerFlag) {
score += 10;
}

if (numCnt == 1) {
score += 10;
} else if (numCnt > 1) {
score += 20;
}

if (symbolCnt == 1) {
score += 10;
} else if (symbolCnt > 1) {
score += 25;
}

if (upperFlag && lowerFlag && numCnt > 0 && symbolCnt > 0) {
score += 5;
} else if ((upperFlag || lowerFlag) && numCnt > 0 && symbolCnt > 0) {
score += 3;
} else if ((upperFlag || lowerFlag) && numCnt > 0) {
score += 2;
}


if (score >= 90) {
return grades[0];
} else if (score >= 80) {
return grades[1];
} else if (score >= 70) {
return grades[2];
} else if (score >= 60) {
return grades[3];
} else if (score >= 50) {
return grades[4];
} else if (score >= 25) {
return grades[5];
} else if (score >= 0) {
return grades[6];
}
return "";
}
}

 

3. 总结

posted on 2023-07-12 00:52  白露~  阅读(76)  评论(0编辑  收藏  举报