HJ80 整型数组合并

1. 题目

读题

HJ80 整型数组合并

 

 

考查点

 

2. 解法

思路

 

代码逻辑

 

具体实现

 

public class HJ080 {

    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);
        int n1 = sc.nextInt();
        int[] arr1 = new int[n1];
        for (int i = 0; i < n1; i++) {
            arr1[i] = sc.nextInt();
        }
        int n2 = sc.nextInt();
        int[] arr2 = new int[n2];
        for (int i = 0; i < n2; i++) {
            arr2[i] = sc.nextInt();
        }
        System.out.println(mergeArray(arr1, arr2));
    }

    public static String mergeArray(int[] arr1, int[] arr2) {

        Arrays.sort(arr1);
        Arrays.sort(arr2);

        StringBuffer sb = new StringBuffer();
        int i = 0, j = 0;
        int last = Integer.MIN_VALUE;
        while (i < arr1.length && j < arr2.length) {

            if (arr1[i] <= arr2[j]) {
                if (arr1[i] == last) {
                    i++;
                    continue;
                }
                sb.append(arr1[i]);
                last = arr1[i];
                i++;
            } else {
                if (arr2[j] == last) {
                    j++;
                    continue;
                }
                sb.append(arr2[j]);
                last = arr2[j];
                j++;
            }
        }
        while (i < arr1.length) {
            if (last == arr1[i]) {
                i++;
                continue;
            }
            sb.append(arr1[i]);
            last = arr1[i];
            i++;
        }
        while (j < arr2.length) {
            if (last == arr2[j]) {
                j++;
                continue;
            }
            sb.append(arr2[j]);
            last = arr2[j];
            j++;
        }


        return sb.toString();
    }
}

3. 总结