String转json
2016-11-23 15:42 sihao560 阅读(520) 评论(0) 编辑 收藏 举报一.下载json 具体到http://www.json.org/上找Java-json下载,并把其放到项目源代码中,这样就可以引用其类对象了
转载地址:http://blog.csdn.net/taxiangwuhen/article/details/7849711
二.具体转化过程
//JSONObject
String jsonMessage = "{\"语文\":\"88\",\"数学\":\"78\",\"计算机\":\"99\"}";
String value1 = null;
try
{
//将字符串转换成jsonObject对象
JSONObject myJsonObject = new JSONObject(jsonMessage);
//获取对应的值
value1 = myJsonObject.getString("数学");
}
catch (JSONException e)
{
}
System.out.println("value1="+value1);
//JSONArray
jsonMessage = "[{'num':'成绩', '外语':88, '历史':65, '地理':99, 'object':{'aaa':'1111','bbb':'2222','cccc':'3333'}}," +
"{'num':'兴趣', '外语':28, '历史':45, '地理':19, 'object':{'aaa':'11a11','bbb':'2222','cccc':'3333'}}," +
"{'num':'爱好', '外语':48, '历史':62, '地理':39, 'object':{'aaa':'11c11','bbb':'2222','cccc':'3333'}}]";
JSONArray myJsonArray;
try
{
myJsonArray = new JSONArray(jsonMessage);
for(int i=0 ; i < myJsonArray.length() ;i++)
{
//获取每一个JsonObject对象
JSONObject myjObject = myJsonArray.getJSONObject(i);
//获取每一个对象中的值
String numString = myjObject.getString("num");
int englishScore = myjObject.getInt("外语");
int historyScore = myjObject.getInt("历史");
int geographyScore = myjObject.getInt("地理");
//获取数组中对象的对象
JSONObject myjObject2 = myjObject.getJSONObject("object");
String aaaString = myjObject2.getString("aaa");
System.out.println("aaaString="+aaaString);
System.out.println("numString="+numString);
System.out.println("englishScore="+englishScore);
System.out.println("historyScore="+historyScore);
System.out.println("geographyScore="+geographyScore);
}
}
catch (JSONException e)
{
}