【DFS】LeetCode 79. 单词搜索
题目链接
思路
DFS
模板题
代码
class Solution {
public boolean exist(char[][] board, String word) {
int m = board.length;
int n = board[0].length;
boolean[][] visited = new boolean[m][n];
for(int i = 0; i < m; i++){
for(int j = 0; j < n; j++){
if(dfs(board, word, 0, i, j, visited)){
return true;
}
}
}
return false;
}
private boolean dfs(char[][] board, String word, int index, int i, int j, boolean[][] visited) {
if(index == word.length()){
return true;
}
if(i < 0 || i >= board.length || j < 0 || j >= board[0].length || visited[i][j] ||
board[i][j] != word.charAt(index)){
return false;
}
visited[i][j] = true;
boolean res =
dfs(board, word, index + 1, i + 1, j, visited) || dfs(board, word, index + 1, i - 1, j, visited) ||
dfs(board, word, index + 1, i, j + 1, visited) ||
dfs(board, word, index + 1, i, j - 1, visited);
visited[i][j] = false;
return res;
}
public static void main(String[] args) {
Solution solution = new Solution();
System.out.println(solution.exist(new char[][]{{'A', 'B', 'C', 'E'}, {'S', 'F', 'C', 'S'},
{'A', 'D', 'E', 'E'}}, "ABCCED"));
}
}
【推荐】国内首个AI IDE,深度理解中文开发场景,立即下载体验Trae
【推荐】编程新体验,更懂你的AI,立即体验豆包MarsCode编程助手
【推荐】抖音旗下AI助手豆包,你的智能百科全书,全免费不限次数
【推荐】轻量又高性能的 SSH 工具 IShell:AI 加持,快人一步
· 被坑几百块钱后,我竟然真的恢复了删除的微信聊天记录!
· 没有Manus邀请码?试试免邀请码的MGX或者开源的OpenManus吧
· 【自荐】一款简洁、开源的在线白板工具 Drawnix
· 园子的第一款AI主题卫衣上架——"HELLO! HOW CAN I ASSIST YOU TODAY
· Docker 太简单,K8s 太复杂?w7panel 让容器管理更轻松!