LeetCode 2022.7.15每日一题 558. 四叉树交集

题目链接

558. 四叉树交集

题目代码

class Solution {
public:
    Node* intersect(Node* quadTree1, Node* quadTree2) {

        if (quadTree1->isLeaf){
            return quadTree1->val ? new Node(true, true, nullptr,
                                             nullptr, nullptr, nullptr) : quadTree2;
        }

        if (quadTree2->isLeaf){
            return quadTree2->val ? new Node(true, true, nullptr,
                                             nullptr, nullptr, nullptr) : quadTree1;
        }

        Node* t1 = intersect(quadTree1->topLeft, quadTree2->topLeft);
        Node* t2 = intersect(quadTree1->topRight, quadTree2->topRight);
        Node* t3 = intersect(quadTree1->bottomLeft, quadTree2->bottomLeft);
        Node* t4 = intersect(quadTree1->bottomRight, quadTree2->bottomRight);

        if (t1->isLeaf && t2->isLeaf && t3->isLeaf && t4->isLeaf){
            if (t1->val == t2->val && t2->val == t3->val && t3->val == t4->val){
                return new Node(t1->val, true, nullptr, nullptr, nullptr, nullptr);
            }
        }

        return new Node(false, false, t1, t2, t3, t4);
    }
};
posted @ 2022-07-15 15:15  Frodo1124  阅读(21)  评论(0编辑  收藏  举报