玲珑学院 1127 咸鱼文章
Time Limit:1s Memory Limit:128MByte
Submissions:474Solved:196
elttiL moT nwod eht teerts sllac ruo god " ehT peek god " . piZ si a peehs god . tuB nehw moT seirt ot yas " peeS " , ti semoc tuo " peek " . dnA ni a yaw moT si thgir . piZ si syawla gnignirb sgniht oh rof su ot peek ! ll'I llet uoy tuoba emos fo meht .
s'piZ tsrif tneserp saw a eohs . tI saw edam fo neerg klis .
eW t'ndid wonk woh piZ dnuof eht eohs . tuB retfa a tnemom yraM , ym gib retsis , dlot em eht eohs dah a egnarts llems . I deddon dna dleh ym eson . " tahW od uoy kniht ti si ? "
" tI sllems ekil gnihtemos rof gninaelc . I kniht enoemos deirt ot naelc a tops ffo eht eohs . nehT eh tup ti ta eht rood ot yrd . "
" gnolA emac piZ . dnA eyb-doog eohs ! " I dias . " eW dluohs ekat ti kcab . "
" eW t'nac " . dias ym rettsis .
" ebyaM elttil moT si thgir , " yraM dias . " ebyaM piZ si a peek god ! "
你正在做英语阅读,可哪知这是一篇咸鱼文章,整个文章的所有单词都是翻转的,你很慌。
不过你是咸鱼程序员,你可以写代码将这篇文章翻转回来,那么翻转回来吧。
#include <iostream> #include <algorithm> #include <cstring> #include <cstdio> #include <vector> #include <queue> #include <cmath> #include <ctime> #include <map> #include <set> using namespace std; #define lowbit(x) (x&(-x)) #define max(x,y) (x>y?x:y) #define min(x,y) (x<y?x:y) #define MAX 100000000000000000 #define MOD 1000000007 #define pi acos(-1.0) #define ei exp(1) #define PI 3.141592653589793238462 #define INF 0x3f3f3f3f3f #define mem(a) (memset(a,0,sizeof(a))) typedef long long ll; vector<string>v; char ch; int main() { string s,ss; while((ch=getchar())!=EOF) { if((ch>='a' && ch<='z') || (ch>='A' && ch<='Z')) s+=ch; else { if(s.size()>0) { reverse(s.begin(),s.end()); v.push_back(s); s=""; } ss+=ch; v.push_back(ss); ss=""; } } for(vector<string>::iterator it=v.begin();it!=v.end();it++) { cout<<*it; } return 0; }