POJ 2503 Babelfish

http://poj.org/problem?id=2503

Babelfish

You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.

Input

Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.

Output

Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".

Sample Input

dog ogday
cat atcay
pig igpay
froot ootfray
loops oopslay

atcay
ittenkay
oopslay

题目思路；
重点是输入，然后map一一映射就可以了，输入可以用getline(cin,a);
下面是mapAC代码

#include <iostream>
#include <cstdio>
#include <cstring>
#include <queue>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <algorithm>
using namespace std;
typedef long long ll;
int main()
{
    map<string,string>m;
    char c[15],b[15];
    string a;
    int i;
    while(getline(cin,a))
    {
        if(a=="") break;
        int x=0,y=0;
        for(i=0;a[i]!=' ';i++)
        {
            c[y++]=a[i];
        }
        c[y++]='\0';
        for(i++;a[i]!='\0';i++)
        {
            b[x++]=a[i];
        }
        b[x++]='\0';
        m[b]=c;
    }
    while(scanf("%s",b)!=EOF)
    {
        if(m.find(b)!=m.end())
            cout<<m[b]<<endl;
        else printf("eh\n");
    }
    return 0;
}

 再来一个字典树代码
时间：1600ms

#include <iostream>
#include <cstdio>
#include <cstring>
#include <queue>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <algorithm>
using namespace std;
typedef long long ll;
struct trie
{
    bool isend;
    char isends[20];
    trie *next[28];
    trie()
    {
        isend=false;
        isends[0]='\0';
        memset(next,0,sizeof(next));
    }
};
trie *root;
void insert(trie *root,char *s,char *ss)
{
    trie *p=root;
    trie *tmp;
    int len=strlen(s);
    int x;
    for(int i=0;i<len;i++)
    {
        x=s[i]-'a';
        if(p->next[x]==NULL)
        {
            tmp=new trie();
            p->next[x]=tmp;
        }
        p=p->next[x];
    }
    strcpy(p->isends,ss);
}
void query(trie *root,char *s)
{
    trie *p=root;
    int x;
    for(int i=0;s[i]!='\0';i++)
    {
        x=s[i]-'a';
        if(p->next[x]==NULL)
        {
            printf("eh\n");
            return;
        }
        p=p->next[x];
    }
    printf("%s\n",p->isends);
}
int main()
{
    char b[15],c[15];
    string a;
    int i=0;
    root=new trie();
    while(getline(cin,a))
    {
        if(a=="") break;
        int x=0,y=0;
        for(i=0;a[i]!=' ';i++)
        {
            c[y++]=a[i];
        }
        c[y++]='\0';
        for(i++;a[i]!='\0';i++)
        {
            b[x++]=a[i];
        }
        b[x++]='\0';
        insert(root,b,c);
    }
    while(scanf("%s",b)!=EOF)
    {
        query(root,b);
    }
    return 0;
}

 再来一个输入处理，时间效率更高
700ms

int main()
{
    char b[15],c[15],a;
    int i;
    root=new trie();
    while(1)
    {
        if((a=getchar())=='\n')break;
        c[0]=a;
        i=1;
        while(1){
            if((a=getchar())==' ') break;
            c[i++]=a;
        }
        c[i]='\0';
        i=0;
        while(1){
            if((a=getchar())=='\n') break;
            b[i++]=a;
        }
        b[i]='\0';
        insert(root,b,c);
    }
    while(scanf("%s",b)!=EOF)
    {
        query(root,b);
    }
    return 0;
}