39. Combination Sum

Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.

The same repeated number may be chosen from C unlimited number of times.

Note:

  • All numbers (including target) will be positive integers.
  • Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
  • The solution set must not contain duplicate combinations.

 

For example, given candidate set 2,3,6,7 and target 7
A solution set is: 
[7] 
[2, 2, 3] 

 

public class Solution {
  public List<List<Integer>> combinationSum(int[] candidates, int target) {
    List<List<Integer>> result = new ArrayList<>();
    if (candidates == null || candidates.length == 0) {
      return result;
    }
    Arrays.sort(candidates);
    helper(candidates, 0, target, new ArrayList<>(), result);
    return result;
  }

  public void helper(int[] candidates, int offset, int target, List<Integer> tmp, List<List<Integer>> result) {
    if (target < 0) {
      return;
    }
    if (target == 0) {
      result.add(new ArrayList<Integer>(tmp));
      return;
    }
    for (int i = offset; i < candidates.length; i++) {
      if (i > 0 && candidates[i] == candidates[i-1]) {
        continue;
      }
      tmp.add(candidates[i]);
      helper(candidates, i, target - candidates[i], tmp, result);
      tmp.remove(tmp.size() - 1);
    }
  }
}

posted on 2015-06-05 07:27  shini  阅读(151)  评论(0编辑  收藏  举报

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