205. Isomorphic Strings

Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg""add", return true.

Given "foo""bar", return false.

Given "paper""title", return true.

Note:
You may assume both s and t have the same length.

用哈希表记录下字符的映射,只要保证1对1映射就行

public class Solution {
  public boolean isIsomorphic(String s, String t) {
    Map<Character, Character> map1 = new HashMap<>();
    Map<Character, Character> map2 = new HashMap<>();
    for (int i = 0; i < s.length(); i++) {
      char a = s.charAt(i);
      char b = t.charAt(i);
      if (map1.containsKey(a) && map1.get(a) != b) {
        return false;
      }
      if (map2.containsKey(b) && map2.get(b) != a) {
        return false;
      }
      map1.put(a, b);
      map2.put(b, a);
    }
    return true;
  }
}

posted on 2015-04-29 11:14  shini  阅读(108)  评论(0编辑  收藏  举报

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