199. Binary Tree Right Side View

Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom.

For example:
Given the following binary tree,

   1            <---
 /   \
2     3         <---
 \     \
  5     4       <---

 

You should return [1, 3, 4].

BFS 遍历树,从右向左遍历,每层只记录第一个。

/**
* Definition for binary tree
* public class TreeNode {
*   int val;
*   TreeNode left;
*   TreeNode right;
*   TreeNode(int x) { val = x; }
* }
*/
public class Solution {
  public List<Integer> rightSideView(TreeNode root) {
    List<Integer> list = new ArrayList<>();
    Queue<TreeNode> queue = new LinkedList<>();
    if (root != null) {
      queue.offer(root);
    }
    int levelNum = 1;
    int nextLevelNum = 0;
    while(!queue.isEmpty()) {
      list.add(queue.peek().val);
      while(levelNum > 0) {
        TreeNode node = queue.poll();
        levelNum --;
        if (node.right != null) {
          queue.add(node.right);
          nextLevelNum++;
        }
        if (node.left != null) {
          queue.add(node.left);
          nextLevelNum++;
        }
      }
      levelNum = nextLevelNum;
      nextLevelNum = 0;
    }
    return list;
  }
}

 

posted on 2015-04-08 06:51  shini  阅读(106)  评论(0编辑  收藏  举报

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