小刘(第二版)
第三章
3.1 uva1585 uvalive3354
题意:错题0分,对题得分为目前位置连续正确数。求总分。
思路:模拟
代码:
![](https://images.cnblogs.com/OutliningIndicators/ContractedBlock.gif)
#include <cstdio> #include <cstring> char str[10000]; int main() { int t; scanf("%d", &t); while (t--) { scanf("%s", str); int res = 0; int now = 0; for (int i = 0; str[i]; i++) { if (str[i] == 'O') now++; else now = 0; res += now; } printf("%d\n", res); } return 0; }
3.2 uva1586 uvalive3900
题意:告诉你四种原子的摩尔质量,现告诉你分子式,求分子的摩尔质量(话说是这么说的么?高中化学忘完了。。)
思路:模拟。最后写成了按字符处理的状态机写法。
代码:
![](https://images.cnblogs.com/OutliningIndicators/ContractedBlock.gif)
#include <cstdio> #include <cstdlib> #include <cstring> double num[5] = {12.01,1.008,16.00,14.01, 0}; char dict[1000]; char str[10000]; #define LOG int main() { int t; scanf("%d\n", &t); dict['C'] = 0; dict['H'] = 1; dict['O'] = 2; dict['N'] = 3; while (t--) { scanf("%s", str); int pre = 4; int now = 0; double res = 0; for (int i = 0; str[i]; i++) { if ('A' <= str[i] && str[i] <= 'Z') { res += num[pre]*(now==0?1:now); // default 1 LOG("pre = %d, now = %d\n", pre, now); now = 0; pre = dict[str[i]]; } if ('0' <= str[i] && str[i] <= '9') { now = now * 10 + str[i] - '0'; } } res += num[pre]*(now==0?1:now); // default 1 printf("%.3lf\n", res); } return 0; }
posted on 2014-12-23 12:18 ShineCheng 阅读(148) 评论(0) 编辑 收藏 举报