uva 177:Paper Folding(模拟 Grade D)
题意:一张纸,每次从右往左对折。折好以后打开,让每个折痕都自然的呈90度。输出形状。
思路:模拟折……每次折想象成把一张纸分成了正面在下的一张和反面在上的一张。维护左边和方向,然后输出。细节有点多。
代码:
#include <cstdio> #include <cstdlib> #include <cstring> #include <algorithm> using namespace std; #define N (1<<13)+10 struct Paper{ int l, r; bool isFace; Paper(){} Paper(int _l, int _r, bool is) : l(_l), r(_r), isFace(is){} }paper[N]; int data[N]; int pp; void flod(Paper &now) { int mid = (now.l+now.r)/2; data[mid] = now.isFace?1:-1; //printf("%d %c %d\n", now.l, "^v"[data[mid]==1], now.r); if( now.isFace ) { paper[pp++] = Paper(mid,now.r,!now.isFace); now.r = mid; } else { paper[pp++] = Paper(mid,now.r,now.isFace); now.r = mid; now.isFace = !now.isFace; } } struct Point{ int x,y; int way; Point(int x=0, int y=0, int way=-1):x(x),y(y),way(way){} }point[N]; enum{ R,U,L,D }; char mat[2000][2000]; void showGraph(int end) { point[0] = Point(0,0,R); //printf("%d,%d,%c\n",0,0,"RULD"[R]); int lmost = 0; int umost = 0; int rmost = 0; int dmost = 0; for (int i = 1; i < end; i++) { int way = (point[i-1].way+data[i]+4)%4; int x = point[i-1].x; int y = point[i-1].y; // 细节:找出现在的位置 switch(point[i-1].way) { case R: y += 1; break; case L: y -= 1; break; case U: x -= 1; break; case D: break; } switch (way) { case R: y += 1; break; case L: y -= 1; break; case U: break; case D: x += 1; break; } point[i] = Point(x, y, way); //printf("%d,%d,%c\n",x,y,"RULD"[way]); umost = min(umost, x); dmost = max(dmost, x); lmost = min(lmost, y); rmost = max(rmost, y); } //printf(" %d \n%d %d\n %d\n", umost, lmost, rmost, dmost); memset(mat, ' ', sizeof(mat)); for (int i = 0; i < end; i++) { mat[point[i].x-umost][point[i].y-lmost] = (point[i].way == L || point[i].way == R)?'_':'|'; } dmost = dmost - umost; rmost = rmost - lmost; for (int i = 0; i <= dmost; i++) { mat[i][rmost+1] = 0; int p = rmost; while (mat[i][p] == ' ') mat[i][p--] = 0; printf("%s\n", mat[i]); } puts("^"); //printf(" %d \n%d %d\n %d\n", umost, lmost, rmost, dmost); } int main() { int n; while (scanf("%d", &n) != EOF) { if (n == 0) break; pp = 0; paper[pp++] = Paper(0,1<<n,true); memset(data, -1, sizeof(data)); for (int i = 0; i < n; i++) { int nowpp = pp; for (int j = 0; j < nowpp; j++) { flod(paper[j]); } } //for (int i = 1; i < (1<<n); i++) { // printf("%c ", "^v"[data[i]==1]); //}puts(""); showGraph(1<<n); } return 0; }
posted on 2014-09-25 23:09 ShineCheng 阅读(410) 评论(0) 编辑 收藏 举报