摘要: select atype,name_list from ( select listagg(aname,',') within group( order by atype) name_list ,atype from listtable where age>0 group by atype) a; / 阅读全文
posted @ 2023-05-08 16:06 Shilo 阅读(795) 评论(0) 推荐(0) 编辑