// [7/25/2014 Sjm]
/*
好几次 Runtime Error(ACCESS_VIOLATION)。。。后来发现：
当有符号数和无符号数出现在同一个表达式中，默认状态下（不做强制类型转换）表达式的值为将结果转化为无符号类型的值。
eg：
int as = 4;
string str = "abc";
cout << str.size() << endl; // 输出值为 3
cout << str.size() - as << endl; // 输出值非 -1
*/
1 // 法一：
2 #include <iostream>
3 #include <cstdlib>
4 #include <cstdio>
5 #include <string>
6 using namespace std;
7 string str, t_str;
8 string arr_str[17] =
9 { "doge",
10 "Doge", "dOge", "doGe", "dogE",
11 "DOge", "DoGe", "DogE", "dOGe", "dOgE", "doGE",
12 "DOGe", "DOgE", "DoGE", "dOGE",
13 "DOGE"
14 };
15
16 void myGet(int pos) {
17 int lim = pos + 4;
18 t_str = "";
19 for (int i = pos; i < lim; ++i) {
20 t_str += str[i];
21 }
22 }
23
24 int main()
25 {
26 //freopen("input.txt", "r", stdin);
27 int ans = 0;
28 while (getline(cin, str)) {
29 if (str.size() < 4) continue;
30 // 加上此判断，防止Runtime Error，或者计算 (str.size() - 4) 时强制类型转换，即：(int)(str.size()) - 4
31 for (int i = 0; i <= (str.size() - 4); ++i) {
32 myGet(i);
33 for (int j = 0; j < 17; ++j) {
34 if (t_str == arr_str[j]) {
35 ans++;
36 break;
37 }
38 }
39 }
40 }
41 printf("%d\n", ans);
42 return 0;
43 }
1 // 法二：
2 #include <iostream>
3 #include <cstdlib>
4 #include <cstdio>
5 #include <string>
6 using namespace std;
7 string str, t_str;
8
9 int main()
10 {
11 //freopen("input.txt", "r", stdin);
12 int ans = 0;
13 while (getline(cin, str)) {
14 if (str.size() < 4) continue;
15 for (int i = 0; i <= (str.size() - 4); ++i) {
16 if (
17 (str[i] == 'D' || str[i] == 'd') &&
18 (str[i + 1] == 'O' || str[i + 1] == 'o') &&
19 (str[i + 2] == 'G' || str[i + 2] == 'g') &&
20 (str[i + 3] == 'E' || str[i + 3] == 'e')) {
21 ans++;
22 }
23 }
24 }
25 printf("%d\n", ans);
26 return 0;
27 }
