BFS + 剪枝 之 hdu 5012 Dice

/*
BFS 遍历所有状态,当寻找到要转到的状态,输出BFS的层数,即答案,否则输出 -1;
注意:
剪枝: 当BFS到某一种状态时,若此状态已在前面所寻找的状态中出现过,则不用再继续从此状态BFS了,因为此状态所能寻找的状态已经在之前都处理过了。
*/
  1 #include <iostream>
  2 #include <cstdlib>
  3 #include <cstdio>
  4 #include <queue>
  5 #include <vector>
  6 #include <map>
  7 using namespace std;
  8 struct myNode {
  9     int Top, Bottom, Left, Right, Front, Back;
 10 };
 11 typedef pair<myNode, int> P;
 12 
 13 myNode node[2];
 14 vector<myNode> vec;
 15 
 16 void myDeal(int myCase, myNode myNd, myNode &t_Nd) {
 17     // top face, bottom face, left face, right face, front face and back face
 18     switch (myCase) {
 19     case 1: {
 20         t_Nd.Top = myNd.Right;
 21         t_Nd.Bottom = myNd.Left;
 22         t_Nd.Left = myNd.Top;
 23         t_Nd.Right = myNd.Bottom;
 24         t_Nd.Front = myNd.Front;
 25         t_Nd.Back = myNd.Back;
 26         return;
 27     }
 28     case 2: {
 29         t_Nd.Top = myNd.Left;
 30         t_Nd.Bottom = myNd.Right;
 31         t_Nd.Left = myNd.Bottom;
 32         t_Nd.Right = myNd.Top;
 33         t_Nd.Front = myNd.Front;
 34         t_Nd.Back = myNd.Back;
 35         return;
 36     }
 37     case 3: {
 38         t_Nd.Top = myNd.Back;
 39         t_Nd.Bottom = myNd.Front;
 40         t_Nd.Front = myNd.Top;
 41         t_Nd.Back = myNd.Bottom;
 42         t_Nd.Left = myNd.Left;
 43         t_Nd.Right = myNd.Right;
 44         return;
 45     }
 46     case 4: {
 47         t_Nd.Top = myNd.Front;
 48         t_Nd.Bottom = myNd.Back;
 49         t_Nd.Front = myNd.Bottom;
 50         t_Nd.Back = myNd.Top;
 51         t_Nd.Left = myNd.Left;
 52         t_Nd.Right = myNd.Right;
 53         return;
 54     }
 55     default:
 56         system("pause");
 57         return;
 58     }
 59 }
 60 
 61 bool myJudge(const myNode n1, const myNode n2) {
 62     if ((n1.Top == n2.Top) && (n1.Bottom == n2.Bottom) && (n1.Front == n2.Front) &&
 63         (n1.Back == n2.Back) && (n1.Left == n2.Left) && (n1.Right == n2.Right)) {
 64         return true;
 65     }
 66     return false;
 67 }
 68 
 69 bool Judge(myNode nd) {
 70     for (int i = 0; i < vec.size(); ++i) {
 71         if (myJudge(vec[i], nd)) {
 72             return true;
 73         }
 74     }
 75     return false;
 76 }
 77 
 78 void Solve() {
 79     queue<P> que;
 80     que.push(P(node[0], 0));
 81     while (!que.empty()) {
 82         P p1 = que.front();
 83         if (Judge(p1.first)){
 84             //cout << "Yes" << endl;
 85             que.pop();
 86             continue;
 87         }
 88         vec.push_back(p1.first);
 89         que.pop();
 90         if (myJudge(p1.first, node[1])) {
 91             printf("%d\n", p1.second);
 92             return;
 93         }
 94         myNode t_Nd;
 95         for (int i = 1; i <= 4; ++i) {
 96             myDeal(i, p1.first, t_Nd);
 97             //cout << t_Nd.Top << " " << t_Nd.Bottom << " " << t_Nd.Left << " " << t_Nd.Right << " " << t_Nd.Front << " " << t_Nd.Back << endl;
 98             que.push(P(t_Nd, p1.second + 1));
 99         }
100     }
101     printf("-1\n");
102 }
103 
104 int main() {
105     //freopen("input.txt", "r", stdin);
106     int n;
107     while (~scanf("%d %d %d %d %d %d", &node[0].Top, &node[0].Bottom, &node[0].Left, &node[0].Right, &node[0].Front, &node[0].Back)) {
108         scanf("%d %d %d %d %d %d", &node[1].Top, &node[1].Bottom, &node[1].Left, &node[1].Right, &node[1].Front, &node[1].Back);
109         Solve();
110         if (!vec.empty()) vec.clear();
111     }
112     return 0;
113 }

 

posted @ 2014-09-17 13:49  JmingS  阅读(186)  评论(0编辑  收藏  举报