第十九次发博不知道用什么标题好

 1 public class Kettle{
 2     int volume;
 3     public Kettle(int water){
 4     volume = water;
 5   }
 6  
 7 public int heatingWater(int needWater){
 8      int needWater1=0;
 9      if(needWater>volume)
10       System.out.println("装不下");
11     }
12         else {
13             needWater1=needWater-2;
14             System.out.println(nedWater1);
15             }
16 
17             return needWater1;
18     }
19 
20 public static void main(String[] args){
21     
22     Kettle k1 = new kettle(60);
23     k1.heatingWater(40);
24 }
 

 

posted @ 2019-04-26 01:17  18软工8班段诗媛  阅读(69)  评论(0编辑  收藏  举报