PL/SQL %type %rowtype
select * from tt3
-- 20年后多少岁
declare
age tt3.age%type;
dif tt3.age%type;
begin
select age into age from tt3 where id=1;
dif := 20; -- 设置一个年龄差
age:= age + dif;
dbms_output.put_line(age);
end;
------------------------------
declare
age tt3.age%type;
dif tt3.age%type :=20; -- 设置一个年龄差
begin
select age into age from tt3 where id=1;
age:= age + dif;
dbms_output.put_line(age);
end;
-------------------
declare
age tt3.age%type;
dif tt3.age%type :=20; -- 设置一个年龄差
begin
select age+dif into age from tt3 where id=1;
dbms_output.put_line(age);
end;
-------------------
declare
age tt3.age%type;
dif age%type :=21; -- 设置一个年龄差
begin
select age+dif into age from tt3 where id=1;
dbms_output.put_line(age);
end;
select * from tt3 where id=1;
-- 不需要一个字段一个字段写出来
declare
my_user tt3%rowtype;
begin
select * into my_user from tt3 where id=1;
dbms_output.put_line( my_user.user_name );
end;
declare
my_user tt3%rowtype;
show_message varchar2(200);
begin
select * into my_user from tt3 where id=1;
show_message:= my_user.user_name || '住在' || my_user.city;
dbms_output.put_line( show_message );
end;
----------
declare
my_user tt3%rowtype;
show_message varchar2(200);
begin
select * into my_user from tt3 where id=1;
show_message:= my_user.user_name || '住在' || my_user.city||',年龄：'||my_user.age||'岁';
dbms_output.put_line( show_message );
end;
---------------
declare
my_user tt3%rowtype;
show_message varchar2(200);
dif number :=20;
begin
select * into my_user from tt3 where id=1;
show_message:= my_user.user_name || '住在' || my_user.city||',年龄：'||my_user.age||'岁，二十年后'||(my_user.age+dif);
dbms_output.put_line( show_message );
end;
