Find Minimum in Rotated Sorted Array

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

You may assume no duplicate exists in the array.

class Solution(object):
    def findMin(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        l = 0
        r = len(nums) - 1
        while l + 1 < r:
            mid = l + (r - l)/2
            if nums[mid] > nums[r]:
                l = mid
            else:
                r = mid
        return min(nums[l], nums[r])