ajax取返回值的方法

转载

var msg1;
function Hosts(domain_name, ip_addr, create_person, create_time, host_num, operation) {

$.ajax({
async:false,
type: "post",
// url: "{{ url_for('sqlmapapi.update_hosts') }}",
data: "domain_name=" + domain_name + "&ip_addr=" + ip_addr + "&create_person=" + create_person +
"&create_time=" + create_time + "&host_num=" + host_num + "&operation=" + operation,
success: function(msg) {
// window.open('/update/hosts/', _self)
// alert(msg)
msg1=msg
}
});
return msg1;
}

 

上面三个地方设置清楚才能取得返回值

这样就可以调用函数并取得返回值:

msg = Hosts(domain_name, ip_addr, create_person, create_time, host_num, operation)

posted @ 2017-06-21 15:42  脚本小娃子  阅读(1533)  评论(0编辑  收藏  举报