字符串乘积运算+连接
摘要:
node = ['160', 'd6', '1'] t5 = '0' * (3 - len(node[-3])) + node[-3] t4 = node[-2][0] + '0' * (4 - len(node[-2])) + node[-2][1:] print t5, t4 阅读全文
posted @ 2011-08-11 11:41 Cheney Shen 阅读(283) 评论(0) 推荐(0) 编辑
posted @ 2011-08-11 11:41 Cheney Shen 阅读(283) 评论(0) 推荐(0) 编辑