jQuery实现拼图小游戏

方法一：

     var id = $(this).prop("id"); //得到当前点击的这个td的ID

                if (parseInt(id) + 3 < 10 && $("td[id=" + (parseInt(id) + 3) + "]").children().length == 0) { //向下移动

                    $(this).find("img").appendTo($("td[id=" + (parseInt(id) + 3) + "]"));
                }
                else if (parseInt(id) % 3 != 0 && $("td[id=" + (parseInt(id) + 1) + "]").children().length == 0) { //向右

                    $(this).find("img").appendTo($("td[id=" + (parseInt(id) + 1) + "]"));
                }
                else if (parseInt(id) % 3 != 1 && $("td[id=" + (parseInt(id) - 1) + "]").children().length == 0) { //向左
                    $(this).find("img").appendTo($("td[id=" + (parseInt(id) - 1) + "]"));
                }
                else if (parseInt(id) - 3 > 0 && $("td[id=" + (parseInt(id) - 3) + "]").children().length == 0) { //向上

                    $(this).find("img").appendTo($("td[id=" + (parseInt(id) - 3) + "]"));
                }

            })；

方法二：

 <script type="text/javascript">
        $(function () {
            var kid = 0;
            //获取空元素的id
            kid = $("#table1").find("td:empty").prop("id");
            $("td").click(function () {
                //获取图片所在位置
                var id = parseInt($(this).prop("id"));
                var RId = parseInt(id) + 1;
                var LId = parseInt(id) - 1;
                var UId = parseInt(id) - 3;
                var DId = parseInt(id) + 3;
                if (kid == RId && (id % 3 != 0)) {
                    $(this).children().remove().appendTo("#" + RId);
                    kid = id;
                }
                if (kid == LId && id % 3 != 1) {
                    $(this).children().remove().appendTo("#" + LId);
                    kid = id;
                }
                if (kid == UId && id > 3) {
                    $(this).children().remove().appendTo("#" + UId);
                    kid = id;
                }
                if (kid == DId && id < 7) {
                    $(this).children().remove().appendTo("#" + DId);
                    kid = id;
                }
            });
        });

    </script>

 

实现类似拼图小游戏有很多种方法。没看懂的朋友们可以私聊我，

随时为你解答。