leetcode 202
202. Happy Number
Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
- 12 + 92 = 82
- 82 + 22 = 68
- 62 + 82 = 100
- 12 + 02 + 02 = 1
利用递归求解,出口设置为参数为1返回true,参数出现过则返回false.
代码如下:
1 class Solution { 2 public: 3 int sum; 4 vector<int> re; 5 bool isHappy(int n) { 6 if(n == 1) 7 { 8 re.clear(); 9 return true; 10 } 11 else 12 { 13 int count = 0; 14 for(int i = 0; i < re.size(); i++) 15 { 16 if(n == re[i]) 17 { 18 count++; 19 } 20 if(count > 1) 21 { 22 return false; 23 } 24 } 25 } 26 sum = 0; 27 while(n) 28 { 29 sum += (n%10) * (n%10); 30 n /= 10; 31 } 32 re.push_back(sum); 33 return isHappy(sum); 34 } 35 };