Shell: 生成随机字符串
生成一个二十位的随机字符串:
#!/bin/bash randstr() { index=0 str="" for i in {a..z}; do arr[index]=$i; index=`expr ${index} + 1`; done for i in {A..Z}; do arr[index]=$i; index=`expr ${index} + 1`; done for i in {0..9}; do arr[index]=$i; index=`expr ${index} + 1`; done for i in {1..20}; do str="$str${arr[$RANDOM%$index]}"; done echo $str } echo `randstr`
posted on 2012-11-24 10:48 Sheldon Xu 阅读(5889) 评论(0) 编辑 收藏 举报