摘要:
http://acm.sdut.edu.cn/sdutoj/problem.php?action=showproblem&problemid=1570递归求解View Code 1 #include<stdio.h> 2 #include<string.h> 3 int count = 0; 4 int a[21][21]; 5 int h, w; 6 void road(int m, int n) 7 { 8 int i, j; 9 if(m == 1&&n == w)10 {11 count++;12 return ;13 ... 阅读全文