记一个生成罗马数字的代码 

 1 int f[15]={1,4,5,9,10,40,50,90,100,400,500,900,1000},num[10];
 2 int co[15][10]={{1},{1,1},{0,1},{1,0,1},{0,0,1},{0,0,1,1},{0,0,0,1},{0,0,1,0,1},{0,0,0,0,1},{0,0,0,0,1,1},{0,0,0,0,0,1},{0,0,0,0,1,0,1},{0,0,0,0,0,0,1}};
 3 char ss[10] = {'I','V','X','L','C','D','M'};
 4 void pre(int x)
 5 {
 6     int i,j;
 7     for(i = 12 ; i >=0 ; i--)
 8     {
 9         if(x>=f[i])
10         {
11             while(x>=f[i])
12             {
13                 x-=f[i];
14                 for(j = 0; j < 7 ; j++)
15                 {
16                     num[j]+=co[i][j];
17                 }
18             }
19         }
20     }
21 }

 

posted @ 2013-02-25 10:33  _雨  阅读(308)  评论(0)  编辑  收藏  举报