[LeetCode]Add Two Numbers
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
即 342+465= 807
码了一下,一直是Memory Limited ,才发现是漏了 l2 = l2->next;l1 = l1->next; 囧
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if(l2==NULL) return l1;
if(l1==NULL) return l2;
ListNode *l3=NULL;
ListNode *p = l3;
int flag=0;
while( l1!=NULL || l2!=NULL ){
int sum = flag;
if(l1!=NULL){
sum += l1->val;
l1 = l1->next;
}
if(l2!=NULL){
sum += l2->val;
l2 = l2->next;
}
int current ;
flag = sum /10;
current= sum%10;
ListNode *tmp = new ListNode(current);
if(l3==NULL){
l3 = tmp;
p = l3;
}else{
p->next = tmp;
p = p->next;
}
}
if ( flag != 0){
ListNode *tmp = new ListNode(flag);
p->next = tmp;
}
return l3;
}
};