最近在AJAX实战书本中找到如下代码：
<html>
<head>
<title>Untitled Page</title>
<script type="text/javascript">
var req=null;
var console=null;
var READY_STATE_UNINITIALIZED=0;
var READY_STATE_LOADING=1;
var READY_STATE_LOADED=2;
var READY_STATE_INTERACTIVE=3;
var READY_STATE_COMPLETE=4;
function getXmlHttpRequest()
{
var xRequest=null;
if(window.XMLHttpRequest)
{
xRequest=new XMLHttpRequest();
}
else if(window.ActiveXObject)
{
xRequest=new ActiveXObject("Microsoft.XMLHTTP");
}
return xRequest;
}
function sendRequest(url,params,HttpMethod)
{
if(!HttpMethod)
{
//这里改成POST
HttpMethod="GET";
}
req=getXmlHttpRequest();
if(req)
{
req.onreadystatechange=onReadyStateChange;
req.open(HttpMethod,url,true);
req.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
req.send(params);
}
}
function onReadyStateChange()
{
var ready=req.readyState;
var date=null;
if(ready == READY_STATE_COMPLETE)
{
data=req.responseText;
}
else
{
data="loading....["+ready+"]";
}
toConsole(data);
}
function toConsole(data)
{
if (console!=null)
{
var newline=document.createElement("div");
console.appendChild(newline);
var txt=document.createTextNode(data);
newline.appendChild(txt);
}
}
window.onload=function()
{
console=document.getElementById('console');
sendRequest("data.txt");
}
</script>
</head>
<body>
<div id='console'></div>
</body>
<html>
把请求的方法改成POST后，死活通不过。改回GET后就可以了。真想不明白，谁可以指教一二？？
