PHP解析json 并获取元素的值

<?php 
$json=
'{
"item1":
{"item11":{"n":"chenling","m":"llll"},"sex":"男","age":"25"},
"item2":
{"item21":"ling","sex":"女","age":"24"}
}';  
$J=json_decode($json); 
echo "通过下面的信息就可以获取里面的信息了</br>";
print_r($J);
print_r("</br>");
echo "测试访问对象内元素</br>";
print_r($J->item1->item11->n."</br>"); 
print_r($J->item1->sex."</br>"); 
//注意不是标准的json
print_r($J->item2->age."</br>"); 
?>

屏幕打印如下

通过下面的信息就可以获取里面的信息了
stdClass Object ( [item1] => stdClass Object ( [item11] => stdClass Object ( [n] => chenling [m] => llll ) [sex] => 男 [age] => 25 ) [item2] => stdClass Object ( [item21] => ling [sex] => 女 [age] => 24 ) ) 
测试访问对象内元素
chenling
男
24