【leetcode】1523. Count Odd Numbers in an Interval Range

题目如下:

Given two non-negative integers low and high. Return the count of odd numbers between low and high (inclusive).

Example 1:

Input: low = 3, high = 7
Output: 3
Explanation: The odd numbers between 3 and 7 are [3,5,7].

Example 2:

Input: low = 8, high = 10
Output: 1
Explanation: The odd numbers between 8 and 10 are [9].

Constraints:

  • 0 <= low <= high <= 10^9

解题思路:很简单的题目,注意边界。

代码如下:

class Solution(object):
    def countOdds(self, low, high):
        """
        :type low: int
        :type high: int
        :rtype: int
        """
        if low % 2 == 0:
            low += 1
        if high % 2 == 0:
            high -= 1
        return (high - low)/2 + 1

 

posted @ 2020-09-14 15:03  seyjs  阅读(225)  评论(0编辑  收藏  举报