关联Left Outer Join的第一条记录
数据准备
CREATE TABLE person (person_id int primary key, firstname varchar2(4), lastname varchar2(9)) / INSERT ALL INTO person (person_id, firstname, lastname) VALUES (1, 'john', 'lennon') INTO person (person_id, firstname, lastname) VALUES (2, 'paul', 'mccartney') SELECT * FROM dual; CREATE TABLE address (person_id int, address_id int primary key, city varchar2(8)) / INSERT ALL INTO address (person_id, address_id, city) VALUES (1, 1, 'new york') INTO address (person_id, address_id, city) VALUES (1, 2, 'england') INTO address (person_id, address_id, city) VALUES (1, 3, 'japan') INTO address (person_id, address_id, city) VALUES (2, 4, 'london') SELECT * FROM dual;
select p.person_id, p.firstname, p.lastname, x.recent_city from person p left join ( select person_id, min(city) -- can change this to max(city). will work regardless of min/max -- important you do this to get the recent: keep(dense_rank last) keep(dense_rank last order by address_id) as recent_city from address group by person_id ) x on x.person_id = p.person_id
Live test: http://www.sqlfiddle.com/#!4/7b1c9/2
本作品采用 知识共享署名-非商业性使用 2.5 中国大陆许可协议进行许可。 |