HDU1272&&POJ1308 小希的迷宫&&Is It A Tree?(并查集)
题意:
中文题不解释
要点:
两题一毛一样,判断是否合并后的结构是一棵树,即结构中应该没有环路,所以合并时如果发现两个根结点是相同的,就说明存在环路了。并且还要满足顶点数=边数+1。这题比较恶心的地方在于,如果一开始输入0,0要输出Yes,输入部分比较难写,而且HDU改题的时候还没提这事,POJ上倒是有说明。
HDU1272:
16711170 | 2016-03-29 13:50:08 | Accepted | 1272 | 62MS | 3368K | 1009 B | C++ | seasonal |
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define maxn 100050
int p[maxn];
bool valid,mark[maxn];
int edge;
void init()
{
valid = true;
edge = 0;
memset(mark, false, sizeof(mark));
for (int i = 1; i < maxn; i++)
p[i] = i;
}
int find(int x)
{
if (p[x] == x) return x;
return p[x] = find(p[x]);
}
void merge(int x, int y)
{
int xx = find(x);
int yy = find(y);
if (xx == yy)
{
valid = false;
return;
}
mark[x] = true;
mark[y] = true;
edge++;
p[xx] = yy;
}
int main()
{
int x, y;
while (~scanf("%d%d", &x, &y))
{
if (x == -1 && y == -1)
break;
if (x == 0 && y == 0) //一开始就是0,0必须输出Yes
{
printf("Yes\n");
continue;
}
init();
merge(x, y);
while (~scanf("%d%d", &x, &y))
{
if (x == 0 && y == 0)
break;
merge(x, y);
}
int node = 0;
for (int i = 1; i < maxn; i++)
if (mark[i])
node++;
if (!valid || (node != edge + 1))
printf("No\n");
else
printf("Yes\n");
}
return 0;
}
POJ1308:
15330358 | Seasonal | 1308 | Accepted | 828K | 0MS | G++ | 1040B | 2016-03-29 21:59:45 |
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define maxn 100050
int p[maxn];
bool valid,mark[maxn];
int edge;
void init()
{
valid = true;
edge = 0;
memset(mark, false, sizeof(mark));
for (int i = 1; i < maxn; i++)
p[i] = i;
}
int find(int x)
{
if (p[x] == x) return x;
return p[x] = find(p[x]);
}
void merge(int x, int y)
{
int xx = find(x);
int yy = find(y);
if (xx == yy)
{
valid = false;
return;
}
mark[x] = true;
mark[y] = true;
edge++;
p[xx] = yy;
}
int main()
{
int x, y,kase=1;
while (~scanf("%d%d", &x, &y))
{
if (x == -1 && y == -1)
break;
if (x == 0 && y == 0) //一开始就是0,0必须输出Yes
{
printf("Case %d is a tree.\n", kase++);
continue;
}
init();
merge(x, y);
while (~scanf("%d%d", &x, &y))
{
if (x == 0 && y == 0)
break;
merge(x, y);
}
int node = 0;
for (int i = 1; i < maxn; i++)
if (mark[i])
node++;
if (!valid || (node != edge + 1))
printf("Case %d is not a tree.\n",kase++);
else
printf("Case %d is a tree.\n",kase++);
}
return 0;
}