JMock / Mockito 使用方式

JMock使用总结

不修改开发代码,程序运行时注入类bugdao,返回mock对象给它

 

不需要注入spring
/*@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = { "classpath:spring.xml", "classpath:spring-hibernate.xml", "classpath:spring-druid.xml" })*/

public class Test1 {

@Tested    //mock的bugservice
//@Autowired  同样spring的注解也不需要
private BugServiceI bugService;

@Injectable    //注入到bugservice
//@Autowired   
private BugDaoI bugDao;

 

@Test
    public void test1() {
final Tbug bug=new Tbug();
        bug.setName("sss");
        bug.setId("1");;
        final Map<String, Object> params = new HashMap<String, Object>();
        params.put("id", "1");
        
           new NonStrictExpectations() {        // Expectations中包含的内部类区块中,体现的是一个录制被测类的逻辑。           
                {  
                    bugDao.get("from Tbug t join fetch t.tbugtype bugType where t.id = :id", params);
                    result = bug;        // mock掉返回值
                    
                    bugService.get("1");
                    result = bug;  
                }  
            };  
            
            Bug b = bugService.get("1");
            System.out.println(b.getName());  //sss
    }

 }

 

Mockito使用总结

不修改开发代码,程序运行时注入类bugdao,返回mock对象给它

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = { "classpath:spring.xml", "classpath:spring-hibernate.xml", "classpath:spring-druid.xml" })
public class Test2 {

@Autowired
    private BugServiceI bugService;
    
@Autowired
    private BugDaoI bugDao;
    
    
@Test
    public void test() {
        bugDao = mock(BugDaoI.class);  
        Tbug bug=new Tbug();
        bug.setName("sss");
        bug.setId("1");;
        
        Map<String, Object> params = new HashMap<String, Object>();
        params.put("id", "1");
        
        doReturn(bug).when(bugDao).get("from Tbug t join fetch t.tbugtype bugType where t.id = :id", params);   //mock
        
         bugService=new BugServiceImpl();
         ReflectionTestUtils.setField(bugService, "bugDao", bugDao);   //注bugDao
         Bug b = bugService.get("1"); 
System.out.println(b.getName());
}

 

posted @ 2017-04-20 23:05  q55091  阅读(1117)  评论(0编辑  收藏  举报