python3 顺时针打印矩阵元素
code
''' 输入一个矩阵,按照从外向里以顺时针的顺序依次打印出每一个数字, 例如,如果输入如下矩阵: [[ 1, 2, 3, 4], [ 5, 6, 7, 8], [ 9, 10, 11, 12], [13, 14, 15, 16]] 则依次打印出数字 1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10. ''' # -*- coding:utf-8 -*- class Solution: # matrix类型为二维列表,需要返回列表 def printMatrix(self, matrix): if matrix == None: return rows = len(matrix) columns = len(matrix[0]) start = 0 while rows > start * 2 and columns > start * 2: self.PrintMatrixInCircle(matrix, columns, rows, start) start += 1 print('') def PrintMatrixInCircle(self, matrix, columns, rows, start): endX = columns - 1 - start endY = rows - 1 - start # 从左到右打印一行 for i in range(start, endX+1): number = matrix[start][i] print("right",number, ' ', end='') # 从上到下打印一行 if start < endY: for i in range(start+1, endY+1): number = matrix[i][endX] print("down",number, ' ', end='') # 从右到左打印一行 if start < endX and start < endY: for i in range(endX-1, start-1, -1): number = matrix[endY][i] print("left",number, ' ', end='') # 从下到上打印一行 if start < endX and start < endY-1: for i in range(endY-1, start, -1): number = matrix[i][start] print("up",number, ' ', end='') matrix = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]] matrix2 = [[1],[2],[3],[4],[5]] matrix3 = [[1,2], [3,4], [5,6], [7,8], [9,10]] S = Solution() S.printMatrix(matrix) S.printMatrix(matrix2) S.printMatrix(matrix3)
outputs
macname@MacdeMBP ~ % python3 test.py right 1 right 2 right 3 right 4 down 8 down 12 down 16 left 15 left 14 left 13 up 9 up 5 right 6 right 7 down 11 left 10 right 1 down 2 down 3 down 4 down 5 right 1 right 2 down 4 down 6 down 8 down 10 left 9 up 7 up 5 up 3 macname@MacdeMBP ~ %