HDU1028——I gnatius and the Princess III

母函数,不解释……

View Code
#include <stdio.h>
#define N 10001

int c1[N], c2[N];

int main()
{
int n,i,j,k;
while (scanf("%d", &n) != EOF )
{
for (i=0;i<=n;i++)
{
c1[i]=0;
c2[i]=0;
}
for (i=0;i<=n;i++)
{
c1[i]=1;
}
for (i=2;i<=n;i++)
{
for (j=0;j<=n;j++)
{
for (k=0;k+j<=n;k+=i)
{
c2[j+k] += c1[j];
}
}
for (j=0;j<=n;j++)
{
c1[j]=c2[j];
c2[j]=0;
}
}
printf("%d\n", c1[n]);
}
return 0;
}

 

posted @ 2011-11-24 20:12  1050768624  阅读(194)  评论(0编辑  收藏  举报