高精A+B Problem

#include <iostream>
#include <cstdio>
 
using namespace std;
int c[100000];
int d[100000];
int e[100000];
 
int main() {
    string a, b;
    cin >> a >> b;
    if (a == "0") {
        cout << b;
        return 0;
    }
    if (b == "0") {
        cout << a;
        return 0;
    }
    for (int i = a.length() - 1; i >= 0; i--) {
        c[i + 1] = a[i] - '0';
 
    }
    for (int i = b.length() - 1; i >= 0; i--) {
        d[i + 1] = b[i] - '0';
    }
    if (a.length() >= b.length()) {
        for (int i = a.length()  ; i > a.length() - b.length(); i--) {
            if (e[i + 1] + c[i ] + d[i - a.length() + b.length() ] >= 10) {
                e[i + 1] += c[i ] + d[i - a.length() + b.length() ] - 10;
                e[i ]++;
 
            } else {
                e[i + 1] += c[i ] + d[i - a.length() + b.length() ];
            }
        }
        for (int i = a.length() - b.length() ; i >= 0; i--) {
            if (e[i + 1] + c[i  ] >= 10) {
                e[i + 1] += c[i ]  - 10;
                e[i ]++;
            } else {
                e[i + 1] += c[i ];
            }
 
        }
        int num = 0;
        while (e[num] == 0) {
            num++;
        }
        for (int i = num; i <= a.length() + 1; i++) {
            cout << e[i];
        }
    } else {
        for (int i = b.length()  ; i > b.length() - a.length(); i--) {
            if (e[i + 1] + c[i - b.length() + a.length()] + d[i] >= 10) {
                e[i + 1] += c[i - b.length() + a.length()] + d[i] - 10;
                e[i ]++;
            } else {
                e[i + 1] += c[i - b.length() + a.length()] + d[i];
            }
        }
        for (int i = b.length() - a.length() ; i >= 0; i--) {
            if (e[i + 1] + d[i  ] >= 10) {
                e[i + 1] += d[i ] - 10;
                e[i ]++;
            } else {
                e[i + 1] += d[i ];
            }
 
        }
        int num = 0;
        while (e[num] == 0) {
            num++;
        }
        for (int i = num; i <= b.length() + 1; i++) {
            cout << e[i];
        }
    }
 
    return 0;
}