面试:数据库基础面试题
基础表结构
student(sno,sname,sage,ssex) 学生表
course(cno,cname,tno) 课程表
sc(sno,cno,score) 成绩表
teacher(tno,tname) 教师表
1、查询课程1的成绩比课程2的成绩高的所有学生的学号
select a.sno from (select sno,score from sc where cno=1) a, (select sno,score from sc where cno=2) b where a.score>b.score and a.sno=b.sno
2、查询平均成绩大于60分的同学的学号和平均成绩
select a.sno as "学号", avg(a.score) as "平均成绩" from (select sno,score from sc) a group by sno having avg(a.score)>60
3、查询所有同学的学号、姓名、选课数、总成绩
select a.sno as 学号, b.sname as 姓名, count(a.cno) as 选课数, sum(a.score) as 总成绩 from sc a, student b where a.sno = b.sno group by a.sno, b.sname 或者 select student.sno as 学号, student.sname as 姓名, count(sc.cno) as 选课数, sum(score) as 总成绩 from student left outer join sc on student.sno = sc.sno group by student.sno, sname
4、查询姓“张”的老师的个数
select count(tno) from teacher where tname like '张%'
5、查询没学过“张三”老师课的同学的学号、姓名
select student.sno,student.sname from student where sno not in (select distinct(sc.sno) from sc,course,teacher where sc.cno=course.cno and teacher.tno=course.tno and teacher.tname='张三')
6、查询同时学过课程1和课程2的同学的学号、姓名
select sno, sname from student where sno in (select sno from sc where sc.cno = 1) and sno in (select sno from sc where sc.cno = 2) 或者 selectc.sno, c.sname from (select sno from sc where sc.cno = 1) a, (select sno from sc where sc.cno = 2) b, student c where a.sno = b.sno and a.sno = c.sno 或者 select student.sno,student.sname from student,sc where student.sno=sc.sno and sc.cno=1 and exists(select * from sc as sc_2 where sc_2.sno=sc.sno and sc_2.cno=2)
7、查询学过“李四”老师所教所有课程的所有同学的学号、姓名
select sno -- 子查询结果如果要当临时表来使用的话需要起个别名(比如这里面的t) from ( -- 学过该老师课程的同学学号(包含只学一门) select sno,count(cno) num from sc where cno in ( -- 该老师教了哪些课程 select cno from course where tno in ( select tno from teacher where tname = '李四' ) ) group by sno ) t where t.num = ( -- 统计该老师总课程数 select count(cno) from course where tno = ( select tno from teacher where tname = '李四' ) )
8、查询课程编号1的成绩比课程编号2的成绩高的所有同学的学号、姓名
select a.sno, a.sname from student a, (select sno, score from sc where cno = 1) b, (select sno, score from sc where cno = 2) c where b.score > c.score and b.sno = c.sno and a.sno = b.sno
9、查询和编号为1002的同学学习的课程完全相同的其他同学学号和姓名
select sc_1.sno from (select cno from sc where sno='1002')a left join sc sc_1 on a.cno = sc_1.cno where sc_1.sno<>'1002' group by sc_1.sno having count(sc_1.cno) = (select count(cno) from sc where sno='1002'); select a.sno,s.sname from (select sno,GROUP_CONCAT(cno order by cno separator ',') as cid_str from sc where sno='1002')b, (select sno,GROUP_CONCAT(cno order by cno separator ',') as cid_str from sc group by sno)a left join student s on a.sno = s.sno where a.cid_str = b.cid_str and a.sno<>'1002';
10、按平平均分从高到低显示所有学生的如下统计报表:学号,企业管理,马克思,UML,数据库,物理,课程数,平均分
select sno as 学号 ,max(case when cno = 1 then score end) AS 企业管理 ,max(case when cno = 2 then score end) AS 马克思 ,max(case when cno = 3 then score end) AS UML ,max(case when cno = 4 then score end) AS 数据库 ,max(case when cno = 5 then score end) AS 物理 ,count(cno) AS 课程数 ,avg(score) AS 平均分 FROM sc GROUP by sno ORDER by avg(score) DESC
11、查询如下课程平均成绩和及格率的百分数(用"1行"显示):企业管理(001),马克思(002),UML(003),数据库(004)
select avg(case when cno = 1 then score end) as 平均分1, avg(case when cno = 2 then score end) as 平均分2, avg(case when cno = 3 then score end) as 平均分3, avg(case when cno = 4 then score end) as 平均分4, 100 * sum(case when cno = 1 and score > 60 then 1 else 0 end) / sum(casewhen cno = 1 then 1 else 0 end) as 及格率1, 100 * sum(case when cno = 2 and score > 60 then 1 else 0 end) / sum(casewhen cno = 2 then 1 else 0 end) as 及格率2, 100 * sum(case when cno = 3 and score > 60 then 1 else 0 end) / sum(casewhen cno = 3 then 1 else 0 end) as 及格率3, 100 * sum(case when cno = 4 and score > 60 then 1 else 0 end) / sum(casewhen cno = 4 then 1 else 0 end) as 及格率4 from sc
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