2022 lesson 31 条件测试，快捷操作 

 1 """
 2 条件测试,
 3 ctrl+alt+l 格式化，对齐，增加空格等
 4 alt+enter 提示操作
 5 """
 6 grade = 70
 7 if grade >= 60:
 8     print("及格")
 9 
10 if grade < 60:
11     print("不及格")
12 
13 if grade == 100:
14     print("满分")
15 
16 if grade != 100:
17     print("不是满分")
18 
19 if grade >= 70 and grade < 90:
20     print("成绩中等")
21 
22 if grade == 66 or grade == 77 or grade == 88 or grade == 99:
23     print("顺口", grade == 66 or grade == 77 or grade == 88 or grade == 99)
24 
25 if grade >= 60:
26     if grade in [60, 70, 80, 90]:
27         print("成绩及格并且以零结尾", grade >= 6 and grade in [60, 70, 80, 90])

两个快捷操作很有用，很快捷。

posted @ 2022-08-02 00:34  scholar-for-ever  阅读(13)  评论(0)  编辑  收藏  举报