冒泡排序_python
def popdata(ls): for i in range(len(ls)): for j in range(i+1,len(ls)): if ls[i]>ls[j]: # tmp=ls[i] # ls[i]=ls[j] # ls[j]=tmp ##序列解包 ls[i],ls[j]=ls[j],ls[i] return ls input=[3,0,9,11,28,190,21,21] print(popdata(input))
[0, 3, 9, 11, 21, 21, 28, 190]
[Finished in 0.5s]
# 总结:1.使用下标(指针)嵌套循环遍历,确定对应位置值较之后的数据是否为最小值
2.采用python序列解包方式,交换值,简洁一些