js获取2个日期内的所有日期

					var oStartDate = window.navToZZT_VACTIONHEAD1[i].Begda.slice(0, 4) + '-' + window.navToZZT_VACTIONHEAD1[i].Begda.slice(4, 6) +
						'-' + window.navToZZT_VACTIONHEAD1[i].Begda.slice(6, 8);
					var oEndDate = window.navToZZT_VACTIONHEAD1[i].Endda.slice(0, 4) + '-' + window.navToZZT_VACTIONHEAD1[i].Endda.slice(4, 6) + '-' +
						window.navToZZT_VACTIONHEAD1[i].Endda.slice(6, 8);
					var startTime = new Date(oStartDate);
					var endTime = new Date(oEndDate);
					var oRefDate;
					var sType = "Type08";
					if (startTime != undefined && endTime != undefined) {
						while ((endTime.getTime() - startTime.getTime()) >= 0) {
							var year = startTime.getFullYear();
							var month = (startTime.getMonth() + 1).toString().length == 1 ? "0" + (startTime.getMonth() + 1).toString() : 
posted @ 2020-02-05 20:25  linhuang  阅读(74)  评论(0编辑  收藏  举报  来源