编程找出 1000 以内的所有完数

一个数如果恰好等于它的因子之和,这个数就称为“完数”。例如 6=1+2+3.编程找出 1000 以内的所有完数。

perfect_number_list = []
 
for perfect_number in range(2, 1000):
    # 找出一个数的所有因子,加入到因数列表里
    factor_list = []
    for factor in range(1, perfect_number):
        if perfect_number % factor == 0:
            factor_list.append(factor)
 
    # 求出这个数的因子之和,用summing表示
    summing = 0
    for i in range(len(factor_list)):
        summing += factor_list[i]
 
    # 判断这个数和因子之和是否相等
    if perfect_number == summing:
        perfect_number_list.append(perfect_number)
        for i in range(len(factor_list)):
            if i == 0:
                print(f'{perfect_number} = {factor_list[i]}', end='')
            if 0 < i <= len(factor_list) - 1:
                print(f'+{factor_list[i]}', end='')
        print('\n')
 
print(f'1000以内的所有完数有:{perfect_number_list}')

  

posted @ 2023-05-16 11:44  sangern  阅读(166)  评论(0)    收藏  举报