摘要: select s.* from ( select *, row_number() over (partition by [分组字段] order by [排序字段]) as 别名 from 表名称 ) s where s.别名 = 1 .. 阅读全文
posted @ 2019-11-10 22:15 salv 阅读(789) 评论(0) 推荐(0) 编辑